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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    One mole of a compound AB reacts with one mole of a compound CD according to the equation                   AB + CD ⇌ AD + CB.  When equilibrium had been established it was found that \[\frac{3}{4}\]mole each of reactant AB and CD had been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is         [Kerala (Med.) 2003]

    A)                 \[\frac{9}{16}\]

    B)                 \[\frac{1}{9}\]

    C)                 \[\frac{16}{9}\]

    D)                 9

    Correct Answer: D

    Solution :

                                                 \[AB\] + \[CD\]    ⇌    \[AD\] + \[CD\]                    mole at \[t=0\]               1          1                 0          0                    Mole at equilibrium  \[\left( 1-\frac{3}{4} \right)\] \[\left( 1-\frac{3}{4} \right)\] ⇌ \[\left( \frac{3}{4} \right)\]  \[\left( \frac{3}{4} \right)\]                                                       0.25        0.25   ⇌  0.75   0.75                                 \[{{K}_{c}}=\frac{0.75\times 0.75}{0.25\times 0.25}=\frac{0.5625}{0.0625}=9\]


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