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JEE Main & Advanced Chemistry The Solid State / ठोस प्रावस्था Question Bank Crystal structure and Coordination number

  • question_answer
    In \[{{A}^{+}}{{B}^{-}}\]ionic compound, radii of \[{{A}^{+}}\]and \[{{B}^{-}}\]ions are \[180\,\,pm\] and \[187\,\,pm\] respectively. The crystal structure of this compound will be

    A) \[NaCl\] type    

    B) \[CsCl\] type

    C) \[ZnS\] type      

    D) Similar to diamond

    Correct Answer: B

    Solution :

    \[{{r}_{+}}/{{r}_{-}}=\frac{180}{187}=0.962\] which lies in the range of \[0.732-1.000\], hence co-ordination number = 8 i.e. the structure is \[CsCl\] type.


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