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JEE Main & Advanced Chemistry The Solid State / ठोस प्रावस्था Question Bank Crystallography and Lattice

  • question_answer
    For tetrahedral coordination number, the radius ratio \[\frac{{{r}_{{{c}^{+}}}}}{{{r}_{{{a}^{-}}}}}\]  is        [KCET 2000]

    A)                 \[0.732-1.000\] 

    B)                 \[0.414-0.732\]

    C)                 \[0.225-0.414\] 

    D)                 \[0.155-0.225\]

    Correct Answer: C

    Solution :

                    For tetrahedral arrangement co-ordination number is 4 and radius ratio \[({{r}_{+}}/{{r}_{-}})\] is \[0.225-0.414\].


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