Grade | Number of students |
A | 45 |
B | 60 |
C | 80 |
D | 15 |
A) \[{{45}^{o}}\]
B) \[{{81}^{o}}\]
C) \[{{65}^{o}}\]
D) \[{{100}^{o}}\]
Correct Answer: B
Solution :
Total number of students \[=45+~60+80+15=200\] Angle of sector for grade A \[=\frac{~Number\text{ }of\text{ }students\text{ }with\text{ }grade\text{ }A}{Total\text{ }number\text{ }of\text{ }students}\times {{360}^{o}}\] \[=\frac{45}{200}\times {{360}^{o}}={{81}^{o}}\]You need to login to perform this action.
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