A) 0, 1
B) 1, 0
C) 1, 1
D) \[-1,\ 1\]
Correct Answer: C
Solution :
\[{{(1+\omega )}^{7}}=A+B\omega \,\,\,\,\Rightarrow {{(-{{\omega }^{2}})}^{7}}=A+B\omega \] Þ \[=\frac{\cos \,\,4\theta +i\sin \,\,4\theta }{\cos \,\,4\theta -i\sin \,\,4\theta }\] Þ \[{{\omega }^{2}}.{{\omega }^{12}}=-A-B\omega \]Þ\[A+B\omega +{{\omega }^{2}}=0\] Þ \[A=1,B=1\,\] \[\,(\because 1+\omega +{{\omega }^{2}}=0)\]You need to login to perform this action.
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