A) 1
B) - 1
C) i
D) - i
Correct Answer: C
Solution :
\[z=\frac{\sqrt{3}+i}{-2}\] \[\Rightarrow \] \[iz=-\frac{-1+\sqrt{3i}}{2}=-\omega \] \[\Rightarrow \] \[z=\frac{-\omega }{i}=i\omega \]\[\Rightarrow \]\[{{z}^{69}}={{i}^{69}}.{{\omega }^{69}}=i\] \[(\because {{\omega }^{3n}}={{i}^{4n}}=1)\]You need to login to perform this action.
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