A) 0
B) 16
C) \[16\,\omega \]
D) \[16\,{{\omega }^{2}}\]
Correct Answer: C
Solution :
\[{{(3+\omega +3{{\omega }^{2}})}^{4}}\]\[=\,{{(-3\omega +\omega )}^{4}}\] \[[\because \,\,\omega +{{\omega }^{2}}=-1]\] = \[{{(-2\omega )}^{4}}=16{{\omega }^{4}}=16\omega \].You need to login to perform this action.
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