A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
\[\frac{1+i\sqrt{3}}{1-i\sqrt{3}}=\left( \frac{1+i\sqrt{3}}{1-i\sqrt{3}} \right)\,\left( \frac{1+i\sqrt{3}}{1+i\sqrt{3}} \right)=\frac{-2+i2\sqrt{3}}{4}\] \[=\,\frac{-1+i\sqrt{3}}{2}=\omega \] \ \[{{\left( \frac{1+i\sqrt{3}}{1-i\sqrt{3}} \right)}^{n}}={{\omega }^{n}}={{\omega }^{3}}=1\Rightarrow n=3\].You need to login to perform this action.
You will be redirected in
3 sec