A) 3
B) 1
C) 0
D) None of these
Correct Answer: C
Solution :
Given that \[x=a,y=b\omega ,z=c{{\omega }^{2}}\] Then \[\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=\frac{a}{a}+\frac{b\omega }{b}+\frac{c{{\omega }^{2}}}{c}=1+\omega +{{\omega }^{2}}=0\]You need to login to perform this action.
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