A) \[27\,abc\]
B) 0
C) \[3\,abc\]
D) None of these
Correct Answer: A
Solution :
Trick: Put\[a=1,b=1,c=-2\], \[\because \] \[a+b+c=0\] \[\therefore \,\,\,{{(1+\omega -2{{\omega }^{2}})}^{3}}+{{(1+{{\omega }^{2}}-2\omega )}^{3}}\] \[={{(-3{{\omega }^{2}})}^{3}}+{{(-3\omega )}^{3}}=-27-27=-54\] Also option (a) gives the value \[i.e.,\]\[27\times 1\times 1(-2)=-54\]You need to login to perform this action.
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