A) \[1\times {{10}^{-3}}mol%\]
B) \[2\times {{10}^{-3}}mol%\]
C) \[3\times {{10}^{-3}}mol%\]
D) \[4\times {{10}^{-3}}mol%\]
Correct Answer: A
Solution :
As each \[S{{r}^{2+}}\] ion introduces one cation vacancy, therefore concentration of cation vacancies = mol % of \[SrC{{l}_{2}}\] added.You need to login to perform this action.
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