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JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Definition of combinations, Conditional combinations, Division into groups, Derangements

  • question_answer
    In an examination there are three multiple choice questions and each question has 4 choices. Number of ways in which a student can fail to get all answers correct, is [Pb. CET 1990; UPSEAT 2001]

    A) 11

    B) 12

    C) 27

    D) 63

    Correct Answer: D

    Solution :

    Each question can be answered in 4 ways and all questions can be answered correctly in only one way, so required number of ways\[={{4}^{3}}-1=63\].


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