A) 24
B) 18
C) 12
D) 30
Correct Answer: B
Solution :
The 4 odd digits 1, 3, 3, 1 can be arranged in the 4 odd places in \[\frac{4\ !}{2\ !\ 2\ !}=6\] ways and 3 even digits 2, 4, 2 can be arranged in the three even places in \[\frac{3\ !}{2\ !}=3\] ways. Hence the required number of ways\[=6\times 3=18\].You need to login to perform this action.
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