A) 36
B) 574
C) 144
D) 754
Correct Answer: C
Solution :
Out of 7 places, 4 places are odd and 3 even. Therefore 3 vowels can be arranged in 3 even places in \[^{3}{{P}_{3}}\] ways and remaining 4 consonants can be arranged in 4 odd places in \[^{4}{{P}_{4}}\] ways. Hence required no. of ways = \[^{3}{{P}_{3}}\] × \[^{4}{{P}_{4}}\] = 144.You need to login to perform this action.
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