A) 6
B) 12
C) 24
D) 30
Correct Answer: B
Solution :
Numbers which are divisible by 5 have ?5? fixed in extreme right place3 Digit Numbers | 4 Digit Numbers | |||||
H | T | U | Th | H | T | U |
× | × | 5 | × | × | × | 5 |
\[^{3}{{P}_{2}}\] ways | \[^{3}{{P}_{3}}\] ways | |||||
= \[\frac{3!}{1!}\] = \[\,3\times 2\] | = \[\frac{3!}{0!}\] = \[3\times 2\] | |||||
\[\Rightarrow \] Total ways = 12. |
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