A) 133320
B) 533280
C) 53328
D) None of these
Correct Answer: A
Solution :
Sum of the digits in the unit place is \[6(2+4+6+8)=120\] units. Similarly, sum of digits in ten place is 120 tens and in hundredth place is 120 hundreds etc. Sum of all the 24 numbers is \[120(1+10+{{10}^{2}}+{{10}^{3}})=120\times 1111=133320\].You need to login to perform this action.
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