A) \[\frac{4}{5}\]
B) \[\frac{2}{5}\]
C) \[\frac{7}{5}\]
D) \[\frac{9}{25}\]
Correct Answer: D
Solution :
The probability that one test is held \[=2\times \frac{1}{5}\times \frac{4}{5}=\frac{8}{25}\] Probability that one test is held on both days \[=\frac{1}{5}\times \frac{1}{5}=\frac{1}{25}\] Thus the probability that the student misses at least one test \[=\frac{8}{25}+\frac{1}{25}=\frac{9}{25}.\]
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