A) \[\frac{5}{36}\]
B) \[\frac{1}{9}\]
C) \[\frac{2}{9}\]
D) \[\frac{19}{36}\]
Correct Answer: C
Solution :
Total cases \[=36\]. Favourable cases \[=2+4+2=8\] \[\therefore \] The required probability \[=\frac{8}{36}=\frac{2}{9}.\]
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