A) \[\frac{1}{5}\]
B) \[\frac{3}{5}\]
C) \[\frac{3}{40}\]
D) \[\frac{29}{40}\]
Correct Answer: D
Solution :
There are two mutually exclusive cases for the event. \[A=\] India wins the toss and wins the match. \[B=\] India losses the toss and wins the match \ Required probability \[=P(A)+P(B)=\frac{3}{4}\times \frac{4}{5}+\frac{1}{4}\times \frac{1}{2}=\frac{29}{40}\].
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