A) \[\frac{1}{36}\]
B) \[\frac{3}{36}\]
C) \[\frac{5}{36}\]
D) \[\frac{1}{6}\]
Correct Answer: C
Solution :
Probability of getting 1 in first throw \[=\frac{1}{6}\] Probability of not getting 1 in second throws \[=\frac{5}{6}\] Both are independent events, so the required probability \[=\frac{1}{6}\times \frac{5}{6}=\frac{5}{36}\].
You need to login to perform this action.
You will be redirected in
3 sec
