A) \[\frac{3}{8}\]
B) \[\frac{1}{9}\]
C) \[\frac{5}{16}\]
D) None of these
Correct Answer: C
Solution :
The condition will be satisfied, if both get \[0,\,\,1,\,\,2\] or 3 heads. \[\therefore \] Either 0 head by \[A\] and 0 head by \[B\] or 1 head by \[A\] and 1 head by \[B\] or 2 head by \[A\] and 2 head by \[B\] or 3 head by \[A\] and 3 head by \[B\] \[\therefore \]Required probability \[=\left[ \frac{1}{8}\times \frac{1}{8}+\frac{3}{8}\times \frac{3}{8}+\frac{3}{8}\times \frac{3}{8}+\frac{1}{8}\times \frac{1}{8} \right]=\frac{5}{16}\].
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