A) \[\frac{5}{24}\]
B) \[\frac{5}{64}\]
C) \[\frac{3}{32}\]
D) \[\frac{3}{16}\]
Correct Answer: C
Solution :
Required combinations are (2, 2, 1), (1, 2, 2), (2, 1, 2), (1, 3, 1,), (3, 1, 1) and (1, 1, 3) \ Required probability \[=\frac{6}{{{4}^{3}}}=\frac{6}{64}=\frac{3}{32}\].
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