A) \[\frac{p}{16}\]
B) \[{{p}^{16}}\]
C) \[{}^{16}{{C}_{1}}{{p}^{16}}\]
D) \[1-{{(1-p)}^{16}}\]
Correct Answer: D
Solution :
Probability of correct bit appearing is (1 ? p) \ Probability of correct number \[={{(1-p)}^{16}}\] and hence probability of incorrect number \[=1-{{(1-p)}^{16}}\].
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