A) 2/3
B) 1/6
C) 5/6
D) 1/3
Correct Answer: D
Solution :
P (neither A nor B) = \[P(\bar{A}\cap \bar{B})\]= \[P(\bar{A})\,.\,P(\bar{B})\] \[P(\bar{A})=1-P(A)\] = \[1-\frac{1}{2}=\frac{1}{2}\] \[P(\bar{B})=1-P(B)=1-\frac{1}{3}=\frac{2}{3}\] \[\therefore \] \[P(\bar{A}).P(\bar{B})=\frac{1}{2}\times \frac{2}{3}=\frac{1}{3}\].You need to login to perform this action.
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