A) \[\frac{1}{36}\]
B) \[\frac{5}{36}\]
C) \[\frac{1}{6}\]
D) None of these
Correct Answer: C
Solution :
Total number of ways \[=6\times 6=36\] Favourable number of ways = {(1,1) (1,2) (1,3) (1,4) (1, 5) (1,6)} \ Required probability = \[\frac{6}{36}=\frac{1}{6}.\]
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