A) \[\frac{1}{2}\]
B) \[\frac{1}{{{2}^{n}}}\]
C) \[\frac{1}{{{2}^{n-1}}}\]
D) None of these
Correct Answer: A
Solution :
Total number of ways \[=\,{{2}^{n}}\] If head comes odd times, then favourable ways = \[{{2}^{n-1}}.\] \ Required probability \[=\frac{{{2}^{n-1}}}{{{2}^{n}}}=\frac{1}{2}\].
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