A) \[\frac{2}{3}\]
B) \[\frac{1}{6}\]
C) \[\frac{5}{6}\]
D) \[\frac{5}{36}\]
Correct Answer: B
Solution :
Total number of outcomes \[=36\] Favourable number of outcomes = 6 i.e., (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6), \ Required probability \[=\frac{6}{36}=\frac{1}{6}.\]
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