A) \[\frac{2}{9}\]
B) \[\frac{5}{9}\]
C) \[\frac{5}{36}\]
D) \[\frac{7}{36}\]
Correct Answer: D
Solution :
Total number of outcomes \[=36\], For sum = 7, favourable outcomes are 6 i.e., (6, 1); (5, 2); (4, 3); (3, 4); (2, 5); (1, 6) For sum = 12, favourable outcome is only 1 i.e., (6, 6) \ Probability \[=\frac{6}{36}+\frac{1}{36}=\frac{7}{36}\].
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