A) \[\frac{99}{323}\]
B) \[\frac{224}{323}\]
C) \[\frac{100}{323}\]
D) None of these
Correct Answer: A
Solution :
Total number of ways \[=20\times 19\times 18\times 17\] The number of ways in which no pair is selected \[=20\times 18\times 16\times 14\] Hence the required probability \[=1-\frac{20\times 18\times 16\times 14}{20\times 19\times 18\times 17}=\frac{99}{323}.\]
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