A) \[\frac{1}{10}\]
B) \[\frac{1}{15}\]
C) \[\frac{3}{10}\]
D) \[\frac{2}{21}\]
Correct Answer: B
Solution :
We have total number of balls = 10 \[\therefore \] Number of red balls = 3 and number of black balls = 7 and number of balls in the bag = 3 + 7 = 10 \[\therefore \]The probability for taking out one red ball out of 10 balls = \[\frac{3}{10}\] and the probability for taking out one red ball out of remaining 9 balls = \[\frac{2}{9}\] \[\therefore \] Probability for both balls to be red i.e., \[p=\frac{3}{10}\times \frac{2}{9}=\frac{1}{15}\].
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