A) \[\frac{2}{5}\]
B) \[\frac{8}{15}\]
C) \[\frac{6}{11}\]
D) \[\frac{2}{3}\]
Correct Answer: B
Solution :
Required probability \[=\frac{1}{2}\times \frac{2}{5}+\frac{1}{2}\times \frac{4}{6}=\frac{8}{15}.\]
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