JEE Main & Advanced Mathematics Probability Question Bank Definition of probability

  • question_answer
    Probability of throwing 16 in one throw with three dice is [UPSEAT 2004]

    A)                 \[\frac{1}{36}\]    

    B)                 \[\frac{1}{18}\]

    C)                 \[\frac{1}{72}\]    

    D)                 \[\frac{1}{9}\]

    Correct Answer: A

    Solution :

               Total number of favorable ways                    \[n\,(E)=\{(6,6,4)\},\,(6,4,6),\,(4,6,6),\,(5,5,6),\,(5,6,5)(6,5,5)\}=6\]                    Total number of ways = \[n(S)=6\times 6\times 6=216\]                                 \[\therefore \]Required probability = \[\frac{n\,(E)}{n\,(S)}=\frac{6}{216}=\frac{1}{36}\].


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