A) \[\frac{1}{6}\]
B) \[\frac{1}{30}\]
C) \[\frac{11}{80}\]
D) \[\frac{23}{90}\]
Correct Answer: D
Solution :
We have, the number of divisible by 6 in the series form 1 to 90 is 15. \[\therefore \] Number divisible by 8 in the series from 1 to 90 is equal to 11 and the number divisible by both 6 and 8 in series from 1 to 90 = 3. \[\therefore \] Probability of choosing the number divisible by 6 or 8 is \[P=\frac{15+11-3}{90}\] or \[P=\frac{23}{90}\].
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