A) \[\frac{5}{36}\]
B) \[\frac{5}{11}\]
C) \[\frac{6}{11}\]
D) \[\frac{1}{6}\]
Correct Answer: B
Solution :
Required probability =\[\left( \frac{5}{6} \right)\ \left( \frac{1}{6} \right)\ +\ {{\left( \frac{5}{6} \right)}^{3}}\left( \frac{1}{6} \right)+\ {{\left( \frac{5}{6} \right)}^{5}}\left( \frac{1}{6} \right)+...\] = \[\frac{\frac{5}{6}.\frac{1}{6}}{1-{{\left( \frac{5}{6} \right)}^{2}}}=\frac{5}{36-25}=\frac{5}{11}\].
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