A) \[\frac{5}{18}\]
B) \[\frac{7}{36}\]
C) \[\frac{7}{18}\]
D) \[\frac{5}{36}\]
Correct Answer: B
Solution :
The sum 2 can be found in one way i.e. \[(1,\,\,1)\] The sum 8 can be found in five ways i.e. \[(6,\,\,2),\] \[(6,\,\,2),\,(5,\,\,3),\] \[\,(4,\,\,4),\,(3,\,\,5),\,(2,\,\,6)\]. Similarly the sum twelve can be found in one way i.e., \[(6,\,\,6).\] Hence required probability \[=\frac{7}{36}.\]
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