A) \[\frac{103}{2704}\]
B) \[\frac{1}{2704}\]
C) \[\frac{2}{52}\]
D) \[\frac{2601}{2704}\]
Correct Answer: A
Solution :
Required probability is \[1-P\] (no ace of heart) \[=1-\frac{51}{52}.\frac{51}{52}=\frac{(52+51)}{52\,.\,52}=\frac{103}{2704}.\]
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