A) \[\frac{1}{2}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{3}\]
D) \[\frac{1}{6}\]
Correct Answer: B
Solution :
Total number of ways \[=36\] Favourable numbers of cases are \[(1\,\,4),\,(2,\,\,3),\,(3,\,\,2),\] \[(4,\,\,1),\,(1,\,\,5),\,(2,\,\,4),\,(3,\,\,3),\,(4,\,\,2),\,(5,\,\,1)=9\] Hence the required probability \[=\frac{9}{36}=\frac{1}{4}.\]
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