A) \[\frac{2}{3}\]
B) \[\frac{3}{4}\]
C) \[\frac{4}{5}\]
D) \[\frac{3}{5}\]
Correct Answer: D
Solution :
The probability of students not solving the problem are \[1-\frac{1}{3}=\frac{2}{3},\] \[1-\frac{1}{4}=\frac{3}{4}\] and \[1-\frac{1}{5}=\frac{4}{5}\] Therefore the probability that the problem is not solved by any one of them \[=\frac{2}{3}\times \frac{3}{4}\times \frac{4}{5}=\frac{2}{5}\] Hence the probability that problem is solved\[=1-\frac{2}{5}=\frac{3}{5}\].
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