A) \[\frac{4}{15}\]
B) \[\frac{1}{2}\]
C) \[\frac{2}{5}\]
D) \[\frac{2}{3}\]
Correct Answer: D
Solution :
Probability for white ball \[P(W)=\frac{4}{15}\] Probability for red ball \[P(R)=\frac{6}{15}\] Probability (white or red ball) \[=P(W)+P(R)\] \[=\frac{4}{15}+\frac{6}{15}=\frac{10}{15}=\frac{2}{3}\].
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