A) \[\frac{5}{6}\]
B) \[\frac{91}{216}\]
C) \[\frac{1}{36}\]
D) \[\frac{125}{216}\]
Correct Answer: B
Solution :
Required probability is \[1-p\](no die show up 1) \[=1-{{\left( \frac{5}{6} \right)}^{3}}=\frac{216-125}{216}=\frac{91}{216}.\]You need to login to perform this action.
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