A) \[\frac{11}{24}\]
B) \[\frac{1}{12}\]
C) \[\frac{1}{8}\]
D) None of these
Correct Answer: A
Solution :
Here \[P(A)=\frac{1}{2},\] \[P(B)=\frac{1}{3},\] \[P(C)=\frac{1}{4}\] Hence required probability \[=P(A)P(\bar{B})P(\bar{C})+P(\bar{A})P(B)P(\bar{C})+P(\bar{A})P(\bar{B})P(C).\]You need to login to perform this action.
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