A) \[\frac{1}{9}\]
B) \[\frac{1}{72}\]
C) \[\frac{1}{54}\]
D) None of these
Correct Answer: C
Solution :
Three dice can be thrown in \[6\times 6\times 6=216\] ways. \[A\] total 17 can be obtained as \[(5,\,6,\,6)\],\[(6,\,5,\,6),\] \[(6,\,6,\,5)\]. \[A\] total 18 can be obtained as \[(6,\,6,\,6)\]. Hence the required probability \[=\frac{4}{216}=\frac{1}{54}.\]
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