A) 0.00000625
B) 0.18543125
C) 0.00001875
D) 0.81450625
Correct Answer: D
Solution :
We have \[P(\bar{A})=0.05\Rightarrow P(A)=0.95\] Hence the probability that the event will take place in 4 consecutive occasions \[={{\{P(A)\}}^{4}}={{(0.95)}^{4}}=0.81450625\].
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