A) \[\frac{1}{18}\]
B) \[\frac{5}{18}\]
C) \[\frac{7}{18}\]
D) \[\frac{11}{18}\]
Correct Answer: B
Solution :
Ways \[\begin{matrix} 9 & 10 & 11 & 12 \\ \downarrow & \downarrow & \downarrow & \downarrow \\ 4 & 3 & 2 & 1 \\ \end{matrix}\] Hence the required probability \[=\frac{10}{36}=\frac{5}{18}.\]
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