A) \[\frac{1}{n\,!}\]
B) \[1-\frac{1}{n\,!}\]
C) \[1-\frac{1}{n}\]
D) None of these
Correct Answer: B
Solution :
Required probability is \[1-P\] (All letters in right envelope) \[=1-\frac{1}{n\,!}\] {As there are total number of \[n\,!\] ways in which letters can take envelopes and just one way in which they have corresponding envelopes}.
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