A) \[1-{{\left( \frac{2}{7} \right)}^{4}}\]
B) \[4\,{{\left( \frac{2}{7} \right)}^{4}}\]
C) \[{{\left( \frac{3}{7} \right)}^{3}}\]
D) None of these
Correct Answer: C
Solution :
\[P(5\,\text{or}\,6\,\text{or}7)\] in one draw \[=\frac{3}{7}\] \[\therefore \] Probability that in each of 3 draws, the chits bear 5 or 6 or \[7={{\left( \frac{3}{7} \right)}^{3}}.\]
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