A) 0.936
B) 0.784
C) 0.904
D) 0.216
Correct Answer: B
Solution :
Here \[P(A)=0.4\] and \[P(\bar{A})=0.6\] Probability that \[A\] does not happen at all \[={{(0.6)}^{3}}\] Thus required Probability \[=1-{{(0.6)}^{3}}=0.784\].You need to login to perform this action.
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