A) \[\frac{1}{6}\]
B) \[\frac{1}{36}\]
C) \[\frac{1}{18}\]
D) \[\frac{3}{28}\]
Correct Answer: B
Solution :
Same number can appear in 6 ways. Hence required probability \[=\frac{6}{216}=\frac{1}{36}.\]You need to login to perform this action.
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