A) \[\frac{n}{n+1}\]
B) \[\frac{n-1}{n+1}\]
C) \[\frac{1}{n+1}\]
D) None of these
Correct Answer: C
Solution :
\[P\](non-occurrence of \[{{A}_{i}})=1-\frac{1}{i+1}=\frac{i}{i+1}\] \[\therefore \,\,\,P\](non-occurrence of any of events) \[=\left( \frac{1}{2} \right)\,.\,\left( \frac{2}{3} \right)\,.........\left\{ \frac{n}{n+1} \right\}=\frac{1}{n+1}.\]
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