A) \[\frac{1}{144}\]
B) \[\frac{1}{4}\]
C) \[\frac{5}{144}\]
D) \[\frac{7}{144}\]
Correct Answer: C
Solution :
The probaility of drawing two cards of same suit \[=\frac{13}{52}\times \frac{13}{52}\] and it can be of any suit out of 4. So \[P(A)=\frac{4\times 13\times 13}{52\times 52}=\frac{1}{4}\] and \[P(B)=\frac{5}{36}\] Thus \[P(A\cap B)=P(A)\,.\,P(B)=\frac{1}{4}\times \frac{5}{36}=\frac{5}{144}.\]
You need to login to perform this action.
You will be redirected in
3 sec
